思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
斯坦福和耶鲁的研究者发现，Claude 3.7 Sonnet 在特定条件下会以 95.8% 的准确率「近乎逐字逐句」地输出《哈利波特》等受版权保护的作品——这不仅与 Anthropic 长期以来关于「模型只是学习了语言规律」的说法背道而驰，更让该公司对任何人的「蒸馏」指控显得缺乏底气。
。业内人士推荐safew官方下载作为进阶阅读
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Developers losing their ability to distribute apps across all channels due to a single un-reviewable corporate decision
"I get that scepticism. It's earned, not just toward us, but toward the entire tech industry," Vishnevskiy wrote.